Escapeshellarg for php for execution system call like exec($cmd)

Hello Suman,

The PHP code is invalid, maybe that is the reason why an issue is still raised? For example, escapeshellarg.($argc1) does not call escapeshellarg but instead uses it as a constant (that is not defined and thus it is used as a string literal) and concatenates it with $argc1.
On the other hand, I would expect that the code can not be parsed at all since there is also a syntax error in there. But even when I fix the syntax errors the code does not seem to make sense to me (possibly, because it is incomplete). Is this really the code that is executed? If not, please provide the actual code, otherwise it is really hard to say why an issue is still raised.

In regards to the second issue, please create a new thread. Thank you! Also, please have a look at this post before you create the new thread: How to Report a False-positive / False-negative